A satellite in circular orbit 1.609 $\times$ 10⁶ m above the surface of Earth (r_e = 6.436 $\times$ 10⁶ m)has an acceleration toward Earth of A)9.76 m/s² B)6.25 m/s² C)7.80 m/s² D)8.73 m/s² E)15.3 m/s²

Question

Quizplus · Accepted Answer

The gravitational acceleration can be calculated using the formula $ g = \frac{GM}{(r_e + h)^2} $, where $ h $ is the height above Earth's surface. Plugging in the values, the acceleration is approximately 6.25 m/s².

A Satellite in Circular Orbit 1 ×\times× 106 M Above the Surface of Earth (Re = 6

A Satellite in Circular Orbit 1 $\times$ 10⁶ M Above the Surface of Earth (R_e = 6