A 50-kg block rests on a horizontal surface.The coefficient of static friction $\mu$_a = 0.50.The coefficient of kinetic friction $\mu$_k = 0.35.A force of 250 N is applied as shown. A)The block remains at rest. B)The block moves and continues to move at constant velocity. C)The block accelerates to the right. D)The block does not move until is increased to greater than 490 N. E)No conclusions can be drawn concerning the movement of the block from the information given.

Question

Quizplus · Accepted Answer

The force applied is 250 N. The force of friction opposing the motion is 0.5 x 50 x 9.8 N = 245 N. Therefore, the net force acting on the block is 5 N to the right, which causes the block to accelerate. The acceleration can be calculated using Fnet = ma, where Fnet = 5 N and m = 50 kg. Therefore, a = Fnet/m = 0.1 m/s2.

A 50-Kg Block Rests on a Horizontal Surface μ\muμ a = 0

A 50-Kg Block Rests on a Horizontal Surface $\mu$ _a = 0