Container 1 has 8 items,3 of which are defective.Container 2 has 5 items,2 of which are defective.If one item is drawn from each container: What is the probability that one of the items is defective?
A)0.2250
B)0.3000
C)0.0250
D)0.4500
E)0.1500

Question

Quizplus · Accepted Answer

The probability that one item is defective can be calculated by considering two scenarios: either the item from Container 1 is defective and the item from Container 2 is not, or the item from Container 1 is not defective and the item from Container 2 is defective. The probability of drawing a defective item from Container 1 is 3/8, and a non-defective item from Container 2 is 3/5. The probability of drawing a non-defective item from Container 1 is 5/8, and a defective item from Container 2 is 2/5. Adding these probabilities gives (3/8 * 3/5) + (5/8 * 2/5) = 9/40 + 10/40 = 19/40 = 0.475. However, the closest option is 0.4500, which suggests a rounding or approximation in the provided choices.

Container 1 Has 8 Items,3 of Which Are Defective