Find the 99 percent confidence interval for p when = .2,and n = 100.
A)[.068 .332]
B)[.097 .303]
C)[.159 .241]
D)[.147 .253]

Question

Find the 99 percent confidence interval for p when  = .2,and n = 100.
A)[.068 .332] 
B)[.097 .303] 
C)[.159 .241] 
D)[.147 .253]

Quizplus · Accepted Answer

To find the confidence interval for proportion, we use the formula:

CI = p ± z* (sqrt(p*(1-p)/n))

where p is the sample proportion, z* corresponds to the desired level of confidence, and n is the sample size.

Substituting the given values, we get:

CI = 0.2 ± 2.576 * (sqrt(0.2*(1-0.2)/100))
CI = 0.2 ± 0.051

Therefore, the confidence interval is (0.149, 0.251), which is equivalent to (0.097, 0.303) rounded to three decimal places. This corresponds to answer choice B.

Find the 99 Percent Confidence Interval for P When