Last year,during an investigation of the time spent reading e-mails on a daily basis,researchers found that on Monday the average time was 50 minutes.Office workers claim that with the increased spam and junk mail,this time has now increased.To conduct a test,a sample of 25 employees is selected with the following results: sample mean = 51.05 minutes and sample standard deviation = 14.2 minutes.What is the critical value for $\alpha$ = .05 to test the hypotheses.
A)1.711
B)2.064
C)2.060
D)1.708
E)1.645

Question

Quizplus · Accepted Answer

The critical value for F1F1F1S1F1F1F10 = .05 to test the hypotheses is 1.711. This is because the degrees of freedom for the numerator and denominator are both 24, and the critical value for F1F1F1S1F1F1F10 = .05 with these degrees of freedom is 1.711.

Last Year,during an Investigation of the Time Spent Reading E-Mails α\alphaα

Last Year,during an Investigation of the Time Spent Reading E-Mails $\alpha$