Find the angle $\theta$ (in radians and degrees)between the lines.Round your answer to four decimal places for radians and round your answer to one decimal places for degree. $\begin{array} { l }
0.04 x + 0.02 y = 0.06 \
0.07 x - 0.06 y = 0.05
\end{array}$
A) $\theta \approx 1.1903 \text { radians } \approx 69.2 ^ { \circ }$
B) $$\theta \approx 1.1903 \text { radians } \approx 67.2 ^ { \circ }$$
C) $\theta \approx 1.1903 \text { radians } \approx 70.2 ^ { \circ }$
D) $\theta \approx 1.1903 \text { radians } \approx 66.2 ^ { \circ }$
E) $\theta \approx 1.1903 \text { radians } \approx 68.2 ^ { \circ }$

Question

Find the angle $\theta$ (in radians and degrees)between the lines.Round your answer to four decimal places for radians and round your answer to one decimal places for degree.​ $\begin{array} { l } 
0.04 x + 0.02 y = 0.06 \
0.07 x - 0.06 y = 0.05
\end{array}$ ​
A) $\theta \approx 1.1903 \text { radians } \approx 69.2 ^ { \circ }$
B) $$\theta \approx 1.1903 \text { radians } \approx 67.2 ^ { \circ }$$
C) $\theta \approx 1.1903 \text { radians } \approx 70.2 ^ { \circ }$
D) $\theta \approx 1.1903 \text { radians } \approx 66.2 ^ { \circ }$
E) $\theta \approx 1.1903 \text { radians } \approx 68.2 ^ { \circ }$

Quizplus · Accepted Answer

The slopes of the lines are $m_1 = -0.2$ and $m_2 = 1.1667$. So, the angle between the lines is$$\theta = \tan^{-1} \left| \frac{m_2 - m_1}{1 + m_1 m_2} \right| = \tan^{-1} \left| \frac{1.1667 - (-0.2)}{1 + (1.1667)(-0.2)} \right| \approx 1.1903 \text{ radians} \approx 68.2^\circ$$

Find the Angle θ\thetaθ (In Radians and Degrees)between the Lines 0.04x+0.02y=0.060.07x−0.06y=0.05\begin{array} { l } 0.04 x + 0.02 y = 0.06 \\0.07 x - 0.06 y = 0.05\end{array}0.04x+0.02y=0.060.07x−0.06y=0.05​

Find the Angle $\theta$ (In Radians and Degrees)between the Lines $\begin{array} { l } 0.04 x + 0.02 y = 0.06 \\0.07 x - 0.06 y = 0.05\end{array}$