Find the vertex and focus of the parabola. $x ^ { 2 } + 28 y = 0$
A)vertex: (-7 ,0)focus: (0,0)
B)vertex: (7,0)focus: (0,0)
C)vertex: (0,0)focus: (-7,0)
D)vertex: (0,0)focus: (0,-7)
E)vertex: (0,0)focus: (0,7)

Question

Quizplus · Accepted Answer

The given equation is $x^2 + 28y = 0$, which can be rewritten as $x^2 = -28y$. This is a parabola that opens downwards. The standard form of a parabola opening downwards is $x^2 = -4py$, where $p$ is the distance from the vertex to the focus. Comparing the given equation to the standard form, we find that $4p = 28$, so $p = 7$. The vertex of the parabola is at the origin (0,0), and since the parabola opens downwards, the focus is located at (0, -7).

Find the Vertex and Focus of the Parabola x2+28y=0x ^ { 2 } + 28 y = 0x2+28y=0

Find the Vertex and Focus of the Parabola $x ^ { 2 } + 28 y = 0$