Find the vertex and focus of the parabola. $y ^ { 2 } = - \frac { 1 } { 7 } x$
A)vertex: $\left( 0 , - \frac { 5 } { 4 } \right)$ focus: $$\left( 0 , - \frac { 1 } { 28 } \right)$$
B)vertex: $\left( 0 , \frac { 5 } { 4 } \right)$ focus: $$\left( - \frac { 1 } { 7 } , - \frac { 1 } { 7 } \right)$$
C)vertex: (0,0)focus: $\left( - \frac { 1 } { 28 } , 0 \right)$
D)vertex: (0,0)focus: $\left( - \frac { 1 } { 7 } , 0 \right)$
E)vertex: (0,0)focus: $\left( 0 , - \frac { 1 } { 7 } \right)$

Question

Quizplus · Accepted Answer

The given equation is in the form $y^2 = 4ax$, where $a = -\frac{1}{28}$. The vertex of a parabola in this form is at the origin (0,0), and the focus is at $(a,0)$, which gives $\left(-\frac{1}{28}, 0\right)$.

Find the Vertex and Focus of the Parabola y2=−17xy ^ { 2 } = - \frac { 1 } { 7 } xy2=−71​x

Find the Vertex and Focus of the Parabola $y ^ { 2 } = - \frac { 1 } { 7 } x$