Identify the conic as a circle or an ellipse then find the center. $\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 49 } = 1$
A)Circle Center: (0,0)
B)Ellipse Center: (0,0)
C)Circle Center: (7,0)
D)Ellipse Center: (0,7)
E)Circle Center: (7,7)

Question

Identify the conic as a circle or an ellipse then find the center.​ $\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 49 } = 1$ ​
A)Circle Center: (0,0)
B)Ellipse Center: (0,0)
C)Circle Center: (7,0)
D)Ellipse Center: (0,7)
E)​Circle Center: (7,7)

Quizplus · Accepted Answer

The equation is in the form $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ with $a^2 = b^2 = 49$, indicating a circle (since $a = b$). The center is at the origin (0,0) because there are no terms to shift the circle in the x or y direction.

Identify the Conic as a Circle or an Ellipse Then x249+y249=1\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 49 } = 149x2​+49y2​=1

Identify the Conic as a Circle or an Ellipse Then $\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 49 } = 1$