Write the standard form of the equation of the circle with the given characteristics. center: (-1,-5);radius: 6
A) $( x - 1 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36$
B) $( x + 5 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 6$
C) $( x + 5 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 36$
D) $( x - 5 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 6$
E) $( x + 1 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36$

Question

Write the standard form of the equation of the circle with the given characteristics. center: (-1,-5);radius: 6
A) $( x - 1 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36$ 
B) $( x + 5 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 6$
C) $( x + 5 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 36$
D) $( x - 5 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 6$
E) $( x + 1 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36$

Quizplus · Accepted Answer

The standard form of the equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center of the circle and $r$ is the radius. Given the center (-1,-5) and radius 6, the equation becomes $(x + 1)^2 + (y + 5)^2 = 36$.

Write the Standard Form of the Equation of the Circle (x−1)2+(y−5)2=36( x - 1 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36(x−1)2+(y−5)2=36

Write the Standard Form of the Equation of the Circle $( x - 1 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36$