Solved

Complete the Table
-Use the Resulting Solution Points to Sketch

Question 13

Multiple Choice

Complete the table
-Use the resulting solution points to sketch the graph of the equation.
y = -2x + 3
x101492y(x,y) \begin{array} { | c | c | c | c | c | c | } \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\hline y & & & & & \\\hline ( x , y ) & & & & & \\\hline\end{array}


A) x101492y53156(x,y) (1,5) (0,3) (1,1) (4,5) (92,9) \begin{array} { | c | c | c | c | c | c | } \hline \\ x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\\hline \\ y&5 & 3 & 1 & -5 & -6 \\\\\hline \\ (x, y) &(-1,5) & (0,3) & (1,1) & (4,-5) & \left(\frac{9}{2}, 9\right) \\\\\hline\end{array}  Complete the table -Use the resulting solution points to sketch the graph of the equation.  y = -2x + 3  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & & & & & \\ \hline ( x , y )  & & & & & \\ \hline \end{array}   A)  \begin{array} { | c | c | c | c | c | c | }  \hline \\ x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\ y&5 & 3 & 1 & -5 & -6 \\\\ \hline \\ (x, y) &(-1,5)  & (0,3)  & (1,1)  & (4,-5)  & \left(\frac{9}{2}, 9\right) \\\\ \hline \end{array}     B)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1  , 5 )  & ( 0,1 )  & ( 1,3 )  & ( 4 , - 5 )  & (\frac { 9 } { 2 },-6)  \\ \hline \end{array}     C)  \begin{array} { | c | c | c | c | c | c | }  \hline \\x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\y & 5 & 3 & 1 & - 5 & - 6 \\\\ \hline \ x , y )  & ( 5 , - 1 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & \left( \frac { 9 } { 2 } , - 6 \right)  \\\\ \hline \end{array}     D)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & -6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & (\frac{9}{2} ,- 6 )  \\ \hline \end{array}     E)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 0,3 )  & ( 1,1 )  & ( 4 , - 5 )  & \left. (\frac { 9 } { 2 } , - 6 \right)  \\ \hline \end{array}

B) x101492y53156(x,y) (1,5) (0,1) (1,3) (4,5) (92,6) \begin{array} { | c | c | c | c | c | c | } \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\hline y & 5 & 3 & 1 & - 5 & - 6 \\\hline ( x , y ) & ( - 1 , 5 ) & ( 0,1 ) & ( 1,3 ) & ( 4 , - 5 ) & (\frac { 9 } { 2 },-6) \\\hline\end{array}  Complete the table -Use the resulting solution points to sketch the graph of the equation.  y = -2x + 3  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & & & & & \\ \hline ( x , y )  & & & & & \\ \hline \end{array}   A)  \begin{array} { | c | c | c | c | c | c | }  \hline \\ x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\ y&5 & 3 & 1 & -5 & -6 \\\\ \hline \\ (x, y) &(-1,5)  & (0,3)  & (1,1)  & (4,-5)  & \left(\frac{9}{2}, 9\right) \\\\ \hline \end{array}     B)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1  , 5 )  & ( 0,1 )  & ( 1,3 )  & ( 4 , - 5 )  & (\frac { 9 } { 2 },-6)  \\ \hline \end{array}     C)  \begin{array} { | c | c | c | c | c | c | }  \hline \\x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\y & 5 & 3 & 1 & - 5 & - 6 \\\\ \hline \ x , y )  & ( 5 , - 1 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & \left( \frac { 9 } { 2 } , - 6 \right)  \\\\ \hline \end{array}     D)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & -6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & (\frac{9}{2} ,- 6 )  \\ \hline \end{array}     E)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 0,3 )  & ( 1,1 )  & ( 4 , - 5 )  & \left. (\frac { 9 } { 2 } , - 6 \right)  \\ \hline \end{array}

C) x101492y53156(x,y) (5,1) (3,0) (1,1) (4,5) (92,6) \begin{array} { | c | c | c | c | c | c | } \hline \\x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\\hline \\y & 5 & 3 & 1 & - 5 & - 6 \\\\\hline \\( x , y ) & ( 5 , - 1 ) & ( 3,0 ) & ( 1,1 ) & ( 4 , - 5 ) & \left( \frac { 9 } { 2 } , - 6 \right) \\\\\hline\end{array}  Complete the table -Use the resulting solution points to sketch the graph of the equation.  y = -2x + 3  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & & & & & \\ \hline ( x , y )  & & & & & \\ \hline \end{array}   A)  \begin{array} { | c | c | c | c | c | c | }  \hline \\ x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\ y&5 & 3 & 1 & -5 & -6 \\\\ \hline \\ (x, y) &(-1,5)  & (0,3)  & (1,1)  & (4,-5)  & \left(\frac{9}{2}, 9\right) \\\\ \hline \end{array}     B)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1  , 5 )  & ( 0,1 )  & ( 1,3 )  & ( 4 , - 5 )  & (\frac { 9 } { 2 },-6)  \\ \hline \end{array}     C)  \begin{array} { | c | c | c | c | c | c | }  \hline \\x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\y & 5 & 3 & 1 & - 5 & - 6 \\\\ \hline \ x , y )  & ( 5 , - 1 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & \left( \frac { 9 } { 2 } , - 6 \right)  \\\\ \hline \end{array}     D)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & -6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & (\frac{9}{2} ,- 6 )  \\ \hline \end{array}     E)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 0,3 )  & ( 1,1 )  & ( 4 , - 5 )  & \left. (\frac { 9 } { 2 } , - 6 \right)  \\ \hline \end{array}

D) x101492y53156(x,y) (1,5) (3,0) (1,1) (4,5) (92,6) \begin{array} { | c | c | c | c | c | c | } \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\hline y & 5 & 3 & 1 & - 5 & -6 \\\hline ( x , y ) & ( - 1,5 ) & ( 3,0 ) & ( 1,1 ) & ( 4 , - 5 ) & (\frac{9}{2} ,- 6 ) \\\hline\end{array}  Complete the table -Use the resulting solution points to sketch the graph of the equation.  y = -2x + 3  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & & & & & \\ \hline ( x , y )  & & & & & \\ \hline \end{array}   A)  \begin{array} { | c | c | c | c | c | c | }  \hline \\ x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\ y&5 & 3 & 1 & -5 & -6 \\\\ \hline \\ (x, y) &(-1,5)  & (0,3)  & (1,1)  & (4,-5)  & \left(\frac{9}{2}, 9\right) \\\\ \hline \end{array}     B)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1  , 5 )  & ( 0,1 )  & ( 1,3 )  & ( 4 , - 5 )  & (\frac { 9 } { 2 },-6)  \\ \hline \end{array}     C)  \begin{array} { | c | c | c | c | c | c | }  \hline \\x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\y & 5 & 3 & 1 & - 5 & - 6 \\\\ \hline \ x , y )  & ( 5 , - 1 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & \left( \frac { 9 } { 2 } , - 6 \right)  \\\\ \hline \end{array}     D)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & -6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & (\frac{9}{2} ,- 6 )  \\ \hline \end{array}     E)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 0,3 )  & ( 1,1 )  & ( 4 , - 5 )  & \left. (\frac { 9 } { 2 } , - 6 \right)  \\ \hline \end{array}

E) x101492y53156(x,y) (1,5) (0,3) (1,1) (4,5) (92,6) \begin{array} { | c | c | c | c | c | c | } \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\hline y & 5 & 3 & 1 & - 5 & - 6 \\\hline ( x , y ) & ( - 1,5 ) & ( 0,3 ) & ( 1,1 ) & ( 4 , - 5 ) & \left. (\frac { 9 } { 2 } , - 6 \right) \\\hline\end{array}
 Complete the table -Use the resulting solution points to sketch the graph of the equation.  y = -2x + 3  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & & & & & \\ \hline ( x , y )  & & & & & \\ \hline \end{array}   A)  \begin{array} { | c | c | c | c | c | c | }  \hline \\ x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\ y&5 & 3 & 1 & -5 & -6 \\\\ \hline \\ (x, y) &(-1,5)  & (0,3)  & (1,1)  & (4,-5)  & \left(\frac{9}{2}, 9\right) \\\\ \hline \end{array}     B)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1  , 5 )  & ( 0,1 )  & ( 1,3 )  & ( 4 , - 5 )  & (\frac { 9 } { 2 },-6)  \\ \hline \end{array}     C)  \begin{array} { | c | c | c | c | c | c | }  \hline \\x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\\\ \hline \\y & 5 & 3 & 1 & - 5 & - 6 \\\\ \hline \ x , y )  & ( 5 , - 1 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & \left( \frac { 9 } { 2 } , - 6 \right)  \\\\ \hline \end{array}     D)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & -6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 3,0 )  & ( 1,1 )  & ( 4 , - 5 )  & (\frac{9}{2} ,- 6 )  \\ \hline \end{array}     E)  \begin{array} { | c | c | c | c | c | c | }  \hline x & - 1 & 0 & 1 & 4 & \frac { 9 } { 2 } \\ \hline y & 5 & 3 & 1 & - 5 & - 6 \\ \hline ( x , y )  & ( - 1,5 )  & ( 0,3 )  & ( 1,1 )  & ( 4 , - 5 )  & \left. (\frac { 9 } { 2 } , - 6 \right)  \\ \hline \end{array}

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