Find all real values of x such that f(x)= 0. $$f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }$$
A)x = ±12
B)x = ±13
C)x = ±11
D)x = ±10
E)x = ±9

Question

Find all real values of x such that f(x)= 0. $$f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }$$ 
A)x = ±12
B)x = ±13
C)x = ±11
D)x = ±10
E)x = ±9

Quizplus · Accepted Answer

To find the values of $x$ for which $f(x) = 0$, set the function equal to zero and solve for $x$:$$0 = \frac{81 - x^2}{3}$$Multiplying both sides by 3 to eliminate the denominator gives:$$0 = 81 - x^2$$Rearranging the equation gives:$$x^2 = 81$$Taking the square root of both sides gives:$$x = ±9$$Therefore, the correct answer is $x = ±9$.

Find All Real Values of X Such That F(x)= 0 f(x)=81−x23f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }f(x)=381−x2​

Find All Real Values of X Such That F(x)= 0 $f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }$