Find the zeroes of the functions algebraically.? $$f ( x ) = \frac { x ^ { 2 } - 14 x + 48 } { 7 x }$$ ?
A) $x = - 8 , x = - 6 , x = \frac { 1 } { 7 }$
B) $x = 8 , x = 6$
C)? $$x = - 8 , x = - 6$$
D) $x = \frac { 1 } { 7 }$
E) $x = 8 , x = 6 , x = \frac { 1 } { 7 }$

Question

Quizplus · Accepted Answer

To find the zeroes of the function, set $f(x) = 0$ and solve for $x$. The denominator $7x$ does not affect the zeroes unless $x = 0$, which would make the function undefined rather than zero. So, focus on the numerator: $x^2 - 14x + 48 = 0$. Factoring this quadratic equation gives $(x - 8)(x - 6) = 0$, leading to the solutions $x = 8$ and $x = 6$.

Find the Zeroes of the Functions Algebraically f(x)=x2−14x+487xf ( x ) = \frac { x ^ { 2 } - 14 x + 48 } { 7 x }f(x)=7xx2−14x+48​

Find the Zeroes of the Functions Algebraically $f ( x ) = \frac { x ^ { 2 } - 14 x + 48 } { 7 x }$