The number of people playing tennis T (in millions)in the United States from 2000 through 2007 can be approximated by the function $T ( t ) = 0.0235 t ^ { 4 } - 0.3401 t ^ { 3 } + 2.556 t ^ { 2 } - 6.86 t + 23.8$ and the U.S.population P (in millions)from 2000 through 2007 can be approximated by the function $P ( t ) = 5.8 t + 224.5$ ,where t represents the year,with t = 0 corresponding to 2000.
Evaluate the function $h ( t ) = \frac { 0.0235 t ^ { 4 } - 0.3401 t ^ { 3 } + 2.556 t ^ { 2 } - 6.86 t + 23.8 } { 5.8 t + 224.5 }$ for t = 0 and 3.
A)h(0)= 0.1060,h(3)= 0.0783
B)h(0)= 0.3060,h(3)= 0.2783
C)h(0)= -0.2060,h(3)= -0.1783
D)h(0)= 0.1783,h(3)= 0.2060
E)h(0)= -0.1060,h(3)= -0.0783

Question

The number of people playing tennis T (in millions)in the United States from 2000 through 2007 can be approximated by the function​ $T ( t ) = 0.0235 t ^ { 4 } - 0.3401 t ^ { 3 } + 2.556 t ^ { 2 } - 6.86 t + 23.8$ ​ and the U.S.population P (in millions)from 2000 through 2007 can be approximated by the function $P ( t ) = 5.8 t + 224.5$ ,where t represents the year,with t = 0 corresponding to 2000.
Evaluate the function $h ( t ) = \frac { 0.0235 t ^ { 4 } - 0.3401 t ^ { 3 } + 2.556 t ^ { 2 } - 6.86 t + 23.8 } { 5.8 t + 224.5 }$ for t = 0 and 3.
A)h(0)= 0.1060,h(3)= 0.0783
B)h(0)= 0.3060,h(3)= 0.2783
C)h(0)= -0.2060,h(3)= -0.1783
D)h(0)= 0.1783,h(3)= 0.2060
E)h(0)= -0.1060,h(3)= -0.0783

Quizplus · Accepted Answer

For t = 0, $h(0) = \frac{23.8}{224.5} = 0.1060$. For t = 3, substituting t = 3 into both the numerator and denominator of $h(t)$ and calculating gives $h(3) = 0.0783$.

The Number of People Playing Tennis T (In Millions)in the United