Find (f + g)(x). $$f ( x ) = x ^ { 2 } + 4 , g ( x ) = \sqrt { 7 - x }$$
A) $$x ^ { 2 } + 4 - \sqrt { 7 - x }$$
B) $x ^ { 2 } + 4 + \sqrt { 7 - x }$
C) $x ^ { 2 } - 4 + \sqrt { 7 + x }$
D) $x ^ { 2 } - 4 - \sqrt { 7 - x }$
E) $x ^ { 2 } - 4 + \sqrt { 7 - x }$

Question

Find (f + g)(x).​ $$f ( x ) = x ^ { 2 } + 4 , g ( x ) = \sqrt { 7 - x }$$ ​
A) $$x ^ { 2 } + 4 - \sqrt { 7 - x }$$
B) $x ^ { 2 } + 4 + \sqrt { 7 - x }$
C) $x ^ { 2 } - 4 + \sqrt { 7 + x }$
D) $x ^ { 2 } - 4 - \sqrt { 7 - x }$
E) $x ^ { 2 } - 4 + \sqrt { 7 - x }$

Quizplus · Accepted Answer

The operation (f + g)(x) means to add the functions f(x) and g(x) together. Therefore, (f + g)(x) = $x^2 + 4 + \sqrt{7 - x}$.

Find (F + G)(x) f(x)=x2+4,g(x)=7−xf ( x ) = x ^ { 2 } + 4 , g ( x ) = \sqrt { 7 - x }f(x)=x2+4,g(x)=7−x​

Find (F + G)(x) $f ( x ) = x ^ { 2 } + 4 , g ( x ) = \sqrt { 7 - x }$