Find the inverse function of g(x)= x² - 3 informally. ? A) $g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x - 3 }$ B) $g ^ { - 1 } ( x ) = ( x + 3 ) ^ { 2 }$ C) $$g ^ { - 1 } ( x ) = x ^ { 2 } + 3$$ D) $g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x + 3 }$ E) $$g ^ { - 1 } ( x ) = ( x - 3 ) ^ { 2 }$$

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The inverse function of $g(x) = x^2 - 3$ is found by solving for $x$ in terms of $y$, where $y = x^2 - 3$. Solving $y + 3 = x^2$ gives $x = \pm \sqrt{y + 3}$. Since inverse functions must be single-valued, we typically choose the principal square root, giving $g^{-1}(x) = \sqrt{x + 3}$.

Find the Inverse Function of G(x)= X2 - 3 Informally g−1(x)=x−32g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x - 3 }g−1(x)=2x−3​

Find the Inverse Function of G(x)= X² - 3 Informally $g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x - 3 }$