Find the vertex of the parabola. y = - x² + 16x - 60 A)(-8,4) B)(8,4) C)(-8,-4) D)(8,-30) E)(4,8)

Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $y = ax^2 + bx + c$ can be found using the formula $(-b/2a, f(-b/2a))$. Here, $a = -1$ and $b = 16$, so the x-coordinate of the vertex is $-16/(2*(-1)) = 8$. Plugging $x = 8$ back into the equation gives $y = -(8)^2 + 16*8 - 60 = -64 + 128 - 60 = 4$. Therefore, the vertex is $(8, 4)$.

Find the Vertex of the Parabola