From the graph of the quadratic function $f ( x ) = - x ^ { 2 } + 12 x + 4$ ,determine the equation of the axis of symmetry.
A) $x = 6$
B) $x = 4$
C) $x = 40$
D) $x = - 12$
E) $x = - 32$

Question

Quizplus · Accepted Answer

The axis of symmetry for a quadratic function in the form $f(x) = ax^2 + bx + c$ is given by the formula $x = -\frac{b}{2a}$. For the given function $f(x) = -x^2 + 12x + 4$, $a = -1$ and $b = 12$, so the axis of symmetry is $x = -\frac{12}{2(-1)} = 6$.

From the Graph of the Quadratic Function f(x)=−x2+12x+4f ( x ) = - x ^ { 2 } + 12 x + 4f(x)=−x2+12x+4

From the Graph of the Quadratic Function $f ( x ) = - x ^ { 2 } + 12 x + 4$