Use long division to divide. $\left( 6 x ^ { 3 } - 27 x ^ { 2 } + 39 x - 18 \right) \div ( 3 x - 6 )$
A) $2 x ^ { 2 } - 5 x + 3 , x \neq \frac { 6 } { 3 }$
B) $2 x ^ { 2 } - 5 x - 3 , x \neq \frac { 6 } { 3 }$
C) $- 2 x ^ { 2 } - 5 x + 3 , x \neq \frac { 6 } { 3 }$
D) $2 x ^ { 2 } + 5 x + 3 , x \neq \frac { 6 } { 3 }$
E) $2 x ^ { 2 } + 5 x - 3 , x \neq \frac { 6 } { 3 }$

Question

Use long division to divide.​ $\left( 6 x ^ { 3 } - 27 x ^ { 2 } + 39 x - 18 \right) \div ( 3 x - 6 )$ ​
A) $2 x ^ { 2 } - 5 x + 3 , x \neq \frac { 6 } { 3 }$
B) $2 x ^ { 2 } - 5 x - 3 , x \neq \frac { 6 } { 3 }$
C) $- 2 x ^ { 2 } - 5 x + 3 , x \neq \frac { 6 } { 3 }$
D) $2 x ^ { 2 } + 5 x + 3 , x \neq \frac { 6 } { 3 }$
E) $2 x ^ { 2 } + 5 x - 3 , x \neq \frac { 6 } { 3 }$

Quizplus · Accepted Answer

Dividing $6x^3 - 27x^2 + 39x - 18$ by $3x - 6$, we factor out a 3 from the divisor to get $3(x - 2)$. The division process gives a quotient of $2x^2 - 5x + 3$ with a remainder of 0, making option A correct.

Use Long Division to Divide (6x3−27x2+39x−18)÷(3x−6)\left( 6 x ^ { 3 } - 27 x ^ { 2 } + 39 x - 18 \right) \div ( 3 x - 6 )(6x3−27x2+39x−18)÷(3x−6)

Use Long Division to Divide $\left( 6 x ^ { 3 } - 27 x ^ { 2 } + 39 x - 18 \right) \div ( 3 x - 6 )$