Use long division to divide. $2 x ^ { 2 } + 14 x + 20 \div x + 5$
A) $2 x - 4 , x \neq - 5$
B) $2 x + 4 , x \neq - 5$
C) $2 x ^ { 2 } - 4 , x \neq - 5$
D) $2 x ^ { 2 } + 4 , x \neq - 5$
E) $2 x ^ { 2 } + 4 x , x \neq - 5$

Question

Use long division to divide.​ $2 x ^ { 2 } + 14 x + 20 \div x + 5$ ​
A) $2 x - 4 , x \neq - 5$
B) $2 x + 4 , x \neq - 5$
C) $2 x ^ { 2 } - 4 , x \neq - 5$
D) $2 x ^ { 2 } + 4 , x \neq - 5$
E) $2 x ^ { 2 } + 4 x , x \neq - 5$

Quizplus · Accepted Answer

When dividing $2x^2 + 14x + 20$ by $x + 5$, the quotient is $2x + 4$ with a remainder of 0, indicating that $x + 5$ divides evenly into the polynomial.

Use Long Division to Divide 2x2+14x+20÷x+52 x ^ { 2 } + 14 x + 20 \div x + 52x2+14x+20÷x+5

Use Long Division to Divide $2 x ^ { 2 } + 14 x + 20 \div x + 5$