Find the zeros (if any)of the rational function. $$f ( x ) = 1 + \frac { 6 } { x ^ { 2 } - 7 }$$
A)±7
B)±6
C)6
D)±1
E)7

Question

Find the zeros (if any)of the rational function.​ $$f ( x ) = 1 + \frac { 6 } { x ^ { 2 } - 7 }$$ ​
A)±7
B)±6
C)6
D)±1
E)​7

Quizplus · Accepted Answer

The zeros of a function occur where the function equals zero. Setting $ f(x) = 0 $, we have $ 1 + \frac{6}{x^2 - 7} = 0 $. Solving for $ x $, we get $ \frac{6}{x^2 - 7} = -1 $, which simplifies to $ x^2 - 7 = -6 $, leading to $ x^2 = 1 $. Thus, $ x = \pm 1 $.

Find the Zeros (If Any)of the Rational Function f(x)=1+6x2−7f ( x ) = 1 + \frac { 6 } { x ^ { 2 } - 7 }f(x)=1+x2−76​

Find the Zeros (If Any)of the Rational Function $f ( x ) = 1 + \frac { 6 } { x ^ { 2 } - 7 }$