Solve the inequality and graph the solution on the real number line. $$\frac { x ^ { 2 } + 4 x } { x ^ { 2 } - 25 } \leq 0$$
A) $$( - 5 , - 4 ] \cup [ 0,5 )$$
B) $$( - 5,4 ] \cup [ 0 , - 5 )$$
C) $$( - 5,4 ] \cup [ 0,5 )$$
D) $$( 5 , - 4 ] \cup [ 0,5 )$$
E) $$( 5,4 ] \cup [ 0,5 )$$

Question

Solve the inequality and graph the solution on the real number line.​ $$\frac { x ^ { 2 } + 4 x } { x ^ { 2 } - 25 } \leq 0$$ ​
A) $$( - 5 , - 4 ] \cup [ 0,5 )$$ 
B) $$( - 5,4 ] \cup [ 0 , - 5 )$$ 
C) $$( - 5,4 ] \cup [ 0,5 )$$ 
D) $$( 5 , - 4 ] \cup [ 0,5 )$$ 
E) $$( 5,4 ] \cup [ 0,5 )$$

Quizplus · Accepted Answer

The Answer of Solve the inequality and graph the solution on the real number line.​ $$\frac { x ^ { 2 } + 4 x } { x ^ { 2 } - 25 } \leq 0$$ ​
A) $$( - 5 , - 4 ] \cup [ 0,5 )$$ 
B) $$( - 5,4 ] \cup [ 0 , - 5 )$$ 
C) $$( - 5,4 ] \cup [ 0,5 )$$ 
D) $$( 5 , - 4 ] \cup [ 0,5 )$$ 
E) $$( 5,4 ] \cup [ 0,5 )$$

Solve the Inequality and Graph the Solution on the Real x2+4xx2−25≤0\frac { x ^ { 2 } + 4 x } { x ^ { 2 } - 25 } \leq 0x2−25x2+4x​≤0

Solve the Inequality and Graph the Solution on the Real $\frac { x ^ { 2 } + 4 x } { x ^ { 2 } - 25 } \leq 0$