Let Q represent a mass of radioactive radium (²²⁶Ra)(in grams),whose half-life is 1599 years.The quantity of radium present after t years is $Q = 5 \left( \frac { 1 } { 2 } \right) ^ { t / 1599 }$ Determine the quantity present after 300 years.Round to the nearest hundredth of a gram. A)0 g B)0.47 g C)5.00 g D)4.39 g E)0.88 g

Question

Quizplus · Accepted Answer

To find the quantity of radium present after 300 years, substitute $t = 300$ into the given formula: $Q = 5 \left( \frac { 1 } { 2 } \right) ^ { 300 / 1599 }$. Calculating this gives $Q \approx 4.39$ grams, rounding to the nearest hundredth.

Let Q Represent a Mass of Radioactive Radium (226Ra)(in Grams),whose Q=5(12)t/1599Q = 5 \left( \frac { 1 } { 2 } \right) ^ { t / 1599 }Q=5(21​)t/1599

Let Q Represent a Mass of Radioactive Radium (²²⁶Ra)(in Grams),whose $Q = 5 \left( \frac { 1 } { 2 } \right) ^ { t / 1599 }$