Solve the exponential equation algebraically.Approximate the result to three decimal places. $e ^ { 2 x } - 7 e ^ { x } - 8 = 0$
A) $\ln 8 \approx 3.079$
B) $\ln 8 \approx 1.079$
C) $\ln 8 \approx 2.079$
D) $\ln 8 \approx 0.079$
E) $\ln 8 \approx 4.079$

Question

Solve the exponential equation algebraically.Approximate the result to three decimal places.​ $e ^ { 2 x } - 7 e ^ { x } - 8 = 0$ ​
A) $\ln 8 \approx 3.079$
B) $\ln 8 \approx 1.079$
C) $\ln 8 \approx 2.079$
D) $\ln 8 \approx 0.079$
E) $\ln 8 \approx 4.079$

Quizplus · Accepted Answer

The Answer of Solve the exponential equation algebraically.Approximate the result to three decimal places.​ $e ^ { 2 x } - 7 e ^ { x } - 8 = 0$ ​
A) $\ln 8 \approx 3.079$
B) $\ln 8 \approx 1.079$
C) $\ln 8 \approx 2.079$
D) $\ln 8 \approx 0.079$
E) $\ln 8 \approx 4.079$

Solve the Exponential Equation Algebraically e2x−7ex−8=0e ^ { 2 x } - 7 e ^ { x } - 8 = 0e2x−7ex−8=0

Solve the Exponential Equation Algebraically $e ^ { 2 x } - 7 e ^ { x } - 8 = 0$