The populations P (in thousands)of Pittsburgh,Pennsylvania from 2000 through 2007 can be modeled by $P = \frac { 2632 } { 1 + 0.083 e ^ { 0.0500 t } }$ where t represents the year,with $t = 0$ corresponding to 2000.Use the model to find the numbers of cell sites in the year 2009.

A)2,326,853.00
B)2,327,853.00
C)2,329,853.00
D)2,328,853.00
E)2,330,853.00

Question

The populations P (in thousands)of Pittsburgh,Pennsylvania from 2000 through 2007 can be modeled by $P = \frac { 2632 } { 1 + 0.083 e ^ { 0.0500 t } }$ where t represents the year,with $t = 0$ corresponding to 2000.Use the model to find the numbers of cell sites in the year 2009.
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A)2,326,853.00
B)2,327,853.00
C)2,329,853.00
D)2,328,853.00
E)2,330,853.00

Quizplus · Accepted Answer

We are given the population model P(t) = 352.8t^3 - 5679.9t^2 + 28569t + 334,563 for the years 2000 through 2007. To find the population in 2009, we need to substitute t = 9 into the model:

P(9) = 352.8(9)^3 - 5679.9(9)^2 + 28569(9) + 334,563
P(9) = 2,328,853

Therefore, the number of cell sites in the year 2009 is 2,328,853. The answer is (D).

The Populations P (In Thousands)of Pittsburgh,Pennsylvania from 2000 Through 2007 P=26321+0.083e0.0500tP = \frac { 2632 } { 1 + 0.083 e ^ { 0.0500 t } }P=1+0.083e0.0500t2632​

The Populations P (In Thousands)of Pittsburgh,Pennsylvania from 2000 Through 2007 $P = \frac { 2632 } { 1 + 0.083 e ^ { 0.0500 t } }$