Given $\sec \theta = \sqrt { 10 }$ and tan ? = 3,determine the following. ?
Cos(90° - ?)
?
A)?cos(90° - ?)= $\frac { 1 } { 3 }$
B)?cos(90° - ?)= $\frac { 3 \sqrt { 10 } } { 10 }$
C)?cos(90° - ?)= $\frac { \sqrt { 10 } } { 10 }$
D)?cos(90° - ?)= 3
E)undefined

Question

Quizplus · Accepted Answer

Cos(90° - θ) = sin(θ). Given tan(θ) = 3, we have sin(θ) = 3/cos(θ). Since sec(θ) = √10, cos(θ) = 1/√10. Thus, sin(θ) = 3√10/10.

Given sec⁡θ=10\sec \theta = \sqrt { 10 }secθ=10​ And Tan ? = 3,determine the Following

Given $\sec \theta = \sqrt { 10 }$ And Tan ? = 3,determine the Following