If $\sin \theta = \frac { \sqrt { 2 } } { 2 }$ ,find the value of ? in degrees $\left( 0 ^ { \circ }

Question

If $\sin \theta = \frac { \sqrt { 2 } } { 2 }$ ,find the value of ? in degrees $\left( 0 ^ { \circ } < \theta < 90 ^ { \circ } \right)$ without the aid of a calculator.
A)? = 30°
B)?? = 45°
C)??? = 90°
D)??? = 75°
E)??? = 15°

Quizplus · Accepted Answer

We know that $\sin 	heta = \frac{\sqrt{2}}{2}$ when $	heta = 45^{\circ}$, because this is the value of sine at the special angle $45^{\circ}$ on the unit circle. Therefore, the answer is $\boxed{	extbf{(B) } 	heta = 45^{\circ}}$.

If sin⁡θ=22\sin \theta = \frac { \sqrt { 2 } } { 2 }sinθ=22​​

If $\sin \theta = \frac { \sqrt { 2 } } { 2 }$