Given the equation below,determine two solutions such that $0 ^ { \circ }

Question

Given the equation below,determine two solutions such that $0 ^ { \circ } < \theta < 360 ^ { \circ }$ . ​cos θ = $- \frac { \sqrt { 3 } } { 2 }$
A)​θ = 225 ${}^\circ$ ,135 ${}^\circ$
B)θ = 135 ${}^\circ$ ,225 ${}^\circ$
C)θ = 150 ${}^\circ$ ,210 ${}^\circ$
D)θ = 300 ${}^\circ$ ,240 ${}^\circ$
E)θ = 30 ${}^\circ$

Quizplus · Accepted Answer

The cosine of an angle is $- \frac { \sqrt { 3 } } { 2 }$ at 150° and 210° within the range of 0° to 360°, corresponding to the second and third quadrants where cosine values are negative.

Given the Equation Below,determine Two Solutions Such That 0∘<θ<360∘0 ^ { \circ } < \theta < 360 ^ { \circ }0∘<θ<360∘

Given the Equation Below,determine Two Solutions Such That $0 ^ { \circ } < \theta < 360 ^ { \circ }$