The projected monthly sales (in thousands of units)of lawn mowers (a seasonal product)are modeled by $$S = 71 + 3 t - 40 \cos \left( \frac { \pi t } { 6 } \right)$$ where t is the time (in months),with t = 1 corresponding to January.Select the graph of the sales function over 1 year.

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B)
C)
D)

Question

The projected monthly sales (in thousands of units)of lawn mowers (a seasonal product)are modeled by​ $$S = 71 + 3 t - 40 \cos \left( \frac { \pi t } { 6 } \right)$$ ​ where t is the time (in months),with t = 1 corresponding to January.Select the graph of the sales function over 1 year.
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A)​ 
B)​ 
C)​ 
D)​

Quizplus · Accepted Answer

Option B shows the graph of the sales function over 1 year, with the x-axis representing the time (in months) and the y-axis representing the sales (in thousands of units). The function starts at around 20,000 units in January, peaks at around 50,000 units in May/June, and then steadily decreases until the end of the year. The other options either do not cover a full year or have incorrect shapes for the function.

The Projected Monthly Sales (In Thousands of Units)of Lawn Mowers S=71+3t−40cos⁡(πt6)S = 71 + 3 t - 40 \cos \left( \frac { \pi t } { 6 } \right)S=71+3t−40cos(6πt​)

The Projected Monthly Sales (In Thousands of Units)of Lawn Mowers $S = 71 + 3 t - 40 \cos \left( \frac { \pi t } { 6 } \right)$