For the simple harmonic motion described by the trigonometric function,find the least positive value of t for which $d = 0$ ? $d = 6 \cos \frac { 6 \pi } { 5 } t$ ?
A) $\frac { 12 } { 5 }$
B) $\frac { 5 } { 12 }$
C) $\frac { 5 } { 6 }$
D) $\frac { 6 } { 5 }$
E) $\frac { 1 } { 6 }$

Question

Quizplus · Accepted Answer

To find the least positive value of $t$ for which $d = 0$, we set the equation to zero and solve for $t$:$$0 = 6 \cos \left( \frac{6\pi}{5} t \right)$$The cosine function equals zero when its argument is an odd multiple of $\frac{\pi}{2}$. Thus, we set:$$\frac{6\pi}{5} t = \frac{\pi}{2}$$Solving for $t$ gives:$$t = \frac{5}{12}$$

For the Simple Harmonic Motion Described by the Trigonometric Function,find d=0d = 0d=0

For the Simple Harmonic Motion Described by the Trigonometric Function,find $d = 0$