If $\sin x = \frac { 1 } { 2 } \text { and } \cos x = \frac { \sqrt { 3 } } { 2 }$ ,evaluate the following function. cot x

A)cot x = $\frac { 2 } { 3 }$ $\sqrt { 3 }$
B)cot x = $\frac { 1 } { 3 }$ $\sqrt { 3 }$
C)cot x = 2
D)cot x = $\frac { 1 } { 3 }$
E)cot x = $\sqrt { 3 }$

Question

If $\sin x = \frac { 1 } { 2 } \text { and } \cos x = \frac { \sqrt { 3 } } { 2 }$ ,evaluate the following function. ​cot x
​
A)​cot x = $\frac { 2 } { 3 }$ $\sqrt { 3 }$
B)​cot x = $\frac { 1 } { 3 }$ $\sqrt { 3 }$
C)​cot x = 2
D)​cot x = $\frac { 1 } { 3 }$
E)​cot x = $\sqrt { 3 }$

Quizplus · Accepted Answer

The cotangent function is defined as $\cot x = \frac{\cos x}{\sin x}$. Given $\sin x = \frac{1}{2}$ and $\cos x = \frac{\sqrt{3}}{2}$, $\cot x = \frac{\sqrt{3}/2}{1/2} = \sqrt{3}$.

If sin⁡x=12 and cos⁡x=32\sin x = \frac { 1 } { 2 } \text { and } \cos x = \frac { \sqrt { 3 } } { 2 }sinx=21​ and cosx=23​​

If $\sin x = \frac { 1 } { 2 } \text { and } \cos x = \frac { \sqrt { 3 } } { 2 }$