Use the given values to evaluate (if possible)three trigonometric functions cos x,csc x,tan x. $\sec x = \sqrt { 3 } , \sin x = - \frac { \sqrt { 6 } } { 3 }$
A) $\begin{array} { l }
\cos x = \frac { \sqrt { 3 } } { 3 } \
\csc x = - \frac { \sqrt { 6 } } { 2 }
\end{array}$ tan x = - $\sqrt { 2 }$

B) $\begin{array} { l }
\cos x = - \frac { \sqrt { 3 } } { 3 } \
\csc x = - \frac { \sqrt { 6 } } { 2 }
\end{array}$ tan x = - $\sqrt { 2 }$
C) $\begin{array} { l }
\cos x = \frac { \sqrt { 6 } } { 6 } \
\csc x = \frac { \sqrt { 6 } } { 2 }
\end{array}$ tan x = $\sqrt { 2 }$

D) $\begin{array} { l }
\cos x = \frac { \sqrt { 3 } } { 3 } \
\csc x = - \frac { \sqrt { 6 } } { 2 }
\end{array}$ tan x = $\sqrt { 2 }$

E) $\begin{array} { l }
\cos x = \frac { \sqrt { 6 } } { 6 } \
\csc x = \frac { \sqrt { 6 } } { 2 }
\end{array}$ tan x = - $\sqrt { 2 }$

Question

Use the given values to evaluate (if possible)three trigonometric functions cos x,csc x,tan x.​ $\sec x = \sqrt { 3 } , \sin x = - \frac { \sqrt { 6 } } { 3 }$
A)​ $\begin{array} { l } 
\cos x = \frac { \sqrt { 3 } } { 3 } \
\csc x = - \frac { \sqrt { 6 } } { 2 }
\end{array}$ tan x = - $\sqrt { 2 }$
​
B)​ $\begin{array} { l } 
\cos x = - \frac { \sqrt { 3 } } { 3 } \
\csc x = - \frac { \sqrt { 6 } } { 2 }
\end{array}$ tan x = - ​ $\sqrt { 2 }$
C)​ $\begin{array} { l } 
\cos x = \frac { \sqrt { 6 } } { 6 } \
\csc x = \frac { \sqrt { 6 } } { 2 }
\end{array}$ ​tan x = $\sqrt { 2 }$
​
D)​ $\begin{array} { l } 
\cos x = \frac { \sqrt { 3 } } { 3 } \
\csc x = - \frac { \sqrt { 6 } } { 2 }
\end{array}$ ​tan x = $\sqrt { 2 }$
​
E)​ $\begin{array} { l } 
\cos x = \frac { \sqrt { 6 } } { 6 } \
\csc x = \frac { \sqrt { 6 } } { 2 }
\end{array}$ ​tan x = - $\sqrt { 2 }$
​

Quizplus · Accepted Answer

Given $\sec x = \sqrt{3}$, we find $\cos x = \frac{1}{\sec x} = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}$. Given $\sin x = -\frac{\sqrt{6}}{3}$, $\csc x = \frac{1}{\sin x} = -\frac{\sqrt{6}}{2}$. For $\tan x = \frac{\sin x}{\cos x} = -\sqrt{2}$.

Use the Given Values to Evaluate (If Possible)three Trigonometric Functions sec⁡x=3,sin⁡x=−63\sec x = \sqrt { 3 } , \sin x = - \frac { \sqrt { 6 } } { 3 }secx=3​,sinx=−36​​

Use the Given Values to Evaluate (If Possible)three Trigonometric Functions $\sec x = \sqrt { 3 } , \sin x = - \frac { \sqrt { 6 } } { 3 }$