Evaluate the expression.? $$\frac { 1 } { \tan x + \cot x }$$ ?
A) $- \sin ^ { 2 } x$
B) $\sin x$
C) $\sin x \cos x$
D) $\cos ^ { 2 } x$
E)0

Question

Quizplus · Accepted Answer

The expression $\frac { 1 } { \tan x + \cot x }$ simplifies to $\sin x \cos x$. This is because $\tan x = \frac{\sin x}{\cos x}$ and $\cot x = \frac{\cos x}{\sin x}$, so when you add them together, you get $\frac{\sin^2 x + \cos^2 x}{\sin x \cos x}$, which simplifies to $\frac{1}{\sin x \cos x}$ due to the Pythagorean identity $\sin^2 x + \cos^2 x = 1$.

Evaluate the Expression 1tan⁡x+cot⁡x\frac { 1 } { \tan x + \cot x }tanx+cotx1​

Evaluate the Expression $\frac { 1 } { \tan x + \cot x }$