Which of the following expressions is equivalent to $$\frac { 3 \tan 8 x + 3 \tan 8 y } { 1 - \tan 8 x \tan 8 y }$$ ? (x ? ?n,y ? ?n,where n is a whole number) ?
A) $\frac { 8 \cot 3 x + 8 \cot 3 y } { \cot 3 x \cot 3 y - 1 }$
B) $\frac { 3 \cot 8 x + 3 \cot 8 y } { \cot 8 x \cot 8 y + 1 }$
C) $$\frac { 3 \cot 8 x + 3 \cot 8 y } { \cot 8 x \cot 8 y - 1 }$$
D) $\frac { 3 \cot 8 x - 3 \cot 8 y } { \cot 8 x \cot 8 y - 1 }$
E) $\frac { 8 \cot 3 x + 8 \cot 3 y } { \cot 3 x \cot 3 y + 1 }$

Question

Quizplus · Accepted Answer

The given expression $\frac { 3 \tan 8 x + 3 \tan 8 y } { 1 - \tan 8 x \tan 8 y }$ is the tangent addition formula, which is equivalent to $\tan(8x + 8y)$. The equivalent expression in terms of cotangent is $\frac { 3 \cot 8 x + 3 \cot 8 y } { \cot 8 x \cot 8 y - 1 }$, which matches option C.

Which of the Following Expressions Is Equivalent To 3tan⁡8x+3tan⁡8y1−tan⁡8xtan⁡8y\frac { 3 \tan 8 x + 3 \tan 8 y } { 1 - \tan 8 x \tan 8 y }1−tan8xtan8y3tan8x+3tan8y​

Which of the Following Expressions Is Equivalent To $\frac { 3 \tan 8 x + 3 \tan 8 y } { 1 - \tan 8 x \tan 8 y }$