Solve the following equation.
Secx - 2 = 0

A) $x = \frac { \pi } { 5 } + 2 n \pi$ and $x = \frac { 7 \pi } { 5 } + 2 n \pi$ ,where n is a integer
B) $x = \frac { \pi } { 3 } + 2 n \pi$ and $x = \frac { 5 \pi } { 3 } + 2 n \pi$ ,where n is a integer
C) $x = \frac { \pi } { 6 } + 2 n \pi$ and $x = \frac { 7 \pi } { 6 } + 2 n \pi$ ,where n is a integer
D) $x = \frac { \pi } { 6 } + 2 n \pi$ and $x = \frac { 5 \pi } { 6 } + 2 n \pi$ ,where n is a integer
E) $x = \frac { \pi } { 4 } + 2 n \pi$ and $x = \frac { 5 \pi } { 4 } + 2 n \pi$ ,where n is a integer

Question

Solve the following equation. ​
Secx - 2 = 0
​
A)​ $x = \frac { \pi } { 5 } + 2 n \pi$ and $x = \frac { 7 \pi } { 5 } + 2 n \pi$ ,where n is a integer
B)​ $x = \frac { \pi } { 3 } + 2 n \pi$ and $x = \frac { 5 \pi } { 3 } + 2 n \pi$ ,where n is a integer
C)​ $x = \frac { \pi } { 6 } + 2 n \pi$ and $x = \frac { 7 \pi } { 6 } + 2 n \pi$ ,where n is a integer
D)​ $x = \frac { \pi } { 6 } + 2 n \pi$ and $x = \frac { 5 \pi } { 6 } + 2 n \pi$ ,where n is a integer
E)​ $x = \frac { \pi } { 4 } + 2 n \pi$ and $x = \frac { 5 \pi } { 4 } + 2 n \pi$ ,where n is a integer

Quizplus · Accepted Answer

Secx = 2 implies cosx = 1/2. The solutions to cosx = 1/2 are $x = \frac{\pi}{3} + 2n\pi$ and $x = \frac{5\pi}{3} + 2n\pi$, where n is an integer.

Solve the Following Equation x=π5+2nπx = \frac { \pi } { 5 } + 2 n \pix=5π​+2nπ

Solve the Following Equation $x = \frac { \pi } { 5 } + 2 n \pi$