Solve the following equation. $\tan 3 x ( 8 \tan x - 8 ) = 0$
A) $\frac { 2 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi$
B) $\frac { \pi } { 2 } + n \pi , \frac { 2 \pi } { 5 } + n \pi$
C) $\frac { \pi } { 3 } + n \pi , \frac { \pi } { 3 } + n \pi$
D) $\frac { n \pi } { 3 } , \frac { \pi } { 4 } + n \pi$
E) $\frac { 4 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi$

Question

Solve the following equation.​ $\tan 3 x ( 8 \tan x - 8 ) = 0$ ​
A) $\frac { 2 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi$
B)​ $\frac { \pi } { 2 } + n \pi , \frac { 2 \pi } { 5 } + n \pi$
C)​ $\frac { \pi } { 3 } + n \pi , \frac { \pi } { 3 } + n \pi$
D)​ $\frac { n \pi } { 3 } , \frac { \pi } { 4 } + n \pi$
E)​ $\frac { 4 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi$

Quizplus · Accepted Answer

The Answer is D

Solve the Following Equation tan⁡3x(8tan⁡x−8)=0\tan 3 x ( 8 \tan x - 8 ) = 0tan3x(8tanx−8)=0

Solve the Following Equation $\tan 3 x ( 8 \tan x - 8 ) = 0$