Solve the following equation. $\sin x ( 5 \sin x + 5 ) = 0$
A) $n \pi , \frac { \pi } { 2 } + 2 n \pi$
B) $\frac { 2 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi$
C) $n \pi , \frac { 3 \pi } { 2 } + 2 n \pi$
D) $\frac { \pi } { 3 } + n \pi , \frac { \pi } { 3 } + n \pi$
E) $\pi , \frac { 5 \pi } { 2 } + 2 n \pi$

Question

Solve the following equation.​ $\sin x ( 5 \sin x + 5 ) = 0$ ​
A)​ $n \pi , \frac { \pi } { 2 } + 2 n \pi$
B)​ $\frac { 2 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi$
C) $n \pi , \frac { 3 \pi } { 2 } + 2 n \pi$
D)​ $\frac { \pi } { 3 } + n \pi , \frac { \pi } { 3 } + n \pi$
E)​ $\pi , \frac { 5 \pi } { 2 } + 2 n \pi$

Quizplus · Accepted Answer

The equation $\sin x ( 5 \sin x + 5 ) = 0$ can be solved by setting each factor equal to zero. For $\sin x = 0$, the solutions are $x = n\pi$, where $n$ is any integer. For $5\sin x + 5 = 0$, or $\sin x = -1$, the solution is $x = \frac{3\pi}{2} + 2n\pi$, where $n$ is any integer. This matches option C.

Solve the Following Equation sin⁡x(5sin⁡x+5)=0\sin x ( 5 \sin x + 5 ) = 0sinx(5sinx+5)=0

Solve the Following Equation $\sin x ( 5 \sin x + 5 ) = 0$