Find the angle between the vectors u and v if $\mathbf { u } = 3 \mathbf { i } - 2 \mathbf { j }$ and $\mathbf { u } = 3 \mathbf { i } + 2 \mathbf { j }$ Round your answer to two decimal places.
A)66.14°
B)68.34°
C)67.38°
D)65.45°
E)68.79°

Question

Quizplus · Accepted Answer

The dot product of u and v is $(3)(3) + (-2)(2) = 5$. The magnitude of u is $\sqrt{3^2 + (-2)^2} = \sqrt{13}$. The magnitude of v is $\sqrt{3^2 + 2^2} = \sqrt{13}$. Therefore, the angle between u and v is $\cos^{-1}\left(\frac{5}{13}\right) \approx 67.38^\circ$.

Find the Angle Between the Vectors U and V If u=3i−2j\mathbf { u } = 3 \mathbf { i } - 2 \mathbf { j }u=3i−2j

Find the Angle Between the Vectors U and V If $\mathbf { u } = 3 \mathbf { i } - 2 \mathbf { j }$