Find the dimensions of the rectangle meeting the specified conditions. The perimeter is 48 meters and the length is 2 meters more than the width.
A)13 m × 11 m
B)16 m × 14 m
C)16 m × 8 m
D)17 m × 15 m
E)12 m × 12 m

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by P = 2(l + w), where P is the perimeter, l is the length, and w is the width. We are given that the perimeter is 48 meters, so we can write:48 = 2(l + w)24 = l + wWe are also given that the length is 2 meters more than the width, so we can write:l = w + 2Substituting this into the first equation, we get:24 = (w + 2) + w24 = 2w + 222 = 2ww = 11Substituting this back into the equation l = w + 2, we get:l = 11 + 2l = 13Therefore, the dimensions of the rectangle are 13 meters by 11 meters.

Find the Dimensions of the Rectangle Meeting the Specified Conditions