Seven hundred gallons of 89-octane gasoline is obtained by mixing 87-octane gasoline with 92-octane gasoline.How much of each type of gasoline is required to obtain the 700 gallons of 89-octane gasoline? Use this system of linear equations there x and y represent the number of gallons of the 87-octane gasoline and 89-octane gasoline. $$\left\{ \begin{array} { c }
x + y = 700 \
87 x + 92 y = 62300
\end{array} \right.$$
A)87-octane: 89 gal;92-octane: 280 gal
B)87-octane: 280 gal;92-octane: 420 gal
C)92-octane: 89 gal;87-octane: 280 gal
D)87-octane: 420 gal;92-octane: 280 gal
E)92-octane: 280 gal;87-octane: 89 gal

Question

​Seven hundred gallons of 89-octane gasoline is obtained by mixing 87-octane gasoline with 92-octane gasoline.How much of each type of gasoline is required to obtain the 700 gallons of 89-octane gasoline? Use this system of linear equations there x and y represent the number of gallons of the 87-octane gasoline and 89-octane gasoline. ​​ $$\left\{ \begin{array} { c } 
x + y = 700 \
87 x + 92 y = 62300
\end{array} \right.$$ ​
A)87​-octane: 89 gal;92-octane: 280 gal ​
B)87​-octane: 280 gal;92-octane: 420 gal​
C)92​​-octane: 89 gal;87-octane: 280 gal
D)​​87-octane: 420 gal;92-octane: 280 gal
E)​​92-octane: 280 gal;87-octane: 89 gal

Quizplus · Accepted Answer

The system of equations represents a mixture problem where x and y are the amounts of 87-octane and 92-octane gasoline, respectively. Solving the system shows that 420 gallons of 87-octane and 280 gallons of 92-octane gasoline are needed.

​Seven Hundred Gallons of 89-Octane Gasoline Is Obtained by Mixing {x+y=70087x+92y=62300\left\{ \begin{array} { c } x + y = 700 \\87 x + 92 y = 62300\end{array} \right.{x+y=70087x+92y=62300​

Seven Hundred Gallons of 89-Octane Gasoline Is Obtained by Mixing $\left\{ \begin{array} { c } x + y = 700 \\87 x + 92 y = 62300\end{array} \right.$