Find A - B. $$A = \left[ \begin{array} { c c }
4 & - 4 \
4 & 5 \
- 3 & 4
\end{array} \right] , B = \left[ \begin{array} { c c }
3 & 8 \
- 3 & - 5 \
3 & 7
\end{array} \right]$$
A) $$\left[ \begin{array} { c c }
1 & - 12 \
7 & 10 \
- 6 & - 3
\end{array} \right]$$
B) $$\left[ \begin{array} { c c }
3 & - 12 \
7 & - 3 \
- 6 & 10
\end{array} \right]$$
C) $$\left[ \begin{array} { c c }
5 & - 12 \
- 6 & 10 \
7 & - 3
\end{array} \right]$$
D) $$\left[ \begin{array} { c c }
- 1 & 10 \
7 & - 12 \
- 6 & - 3
\end{array} \right]$$
E) $$\left[ \begin{array} { c c }
- 3 & - 12 \
10 & 7 \
- 6 & - 3
\end{array} \right]$$

Question

Find A - B.​ $$A = \left[ \begin{array} { c c } 
4 & - 4 \
4 & 5 \
- 3 & 4
\end{array} \right] , B = \left[ \begin{array} { c c } 
3 & 8 \
- 3 & - 5 \
3 & 7
\end{array} \right]$$ ​
A) $$\left[ \begin{array} { c c } 
1 & - 12 \
7 & 10 \
- 6 & - 3
\end{array} \right]$$
B) $$\left[ \begin{array} { c c } 
3 & - 12 \
7 & - 3 \
- 6 & 10
\end{array} \right]$$
C) $$\left[ \begin{array} { c c } 
5 & - 12 \
- 6 & 10 \
7 & - 3
\end{array} \right]$$
D) $$\left[ \begin{array} { c c } 
- 1 & 10 \
7 & - 12 \
- 6 & - 3
\end{array} \right]$$
E) $$\left[ \begin{array} { c c } 
- 3 & - 12 \
10 & 7 \
- 6 & - 3
\end{array} \right]$$

Quizplus · Accepted Answer

A - B means we need to find the elements that are in A but not in B. The only difference between A and B is in the third group of characters. Therefore, the answer is A because it has the same third group of characters as B, and the rest of the characters in A are also in B.

Find a - B ​ A) [1−12710−6−3]\left[ \begin{array} { c c } 1 & - 12 \\7 & 10 \\- 6 & - 3\end{array} \right]​17−6​−1210−3​​

Find a - B
A) $\left[ \begin{array} { c c } 1 & - 12 \\7 & 10 \\- 6 & - 3\end{array} \right]$