Use mathematical induction to solve for all positive integers n. $1 + 2 + 3 + 4 + \ldots + n = ?$
A) $\frac { n ( n + 1 ) } { 2 }$
B) $\frac { ( n + 1 ) } { 2 }$
C) $\frac { n } { 2 } ( 3 n + 1 )$
D) $\frac { n ( n + 1 ) ( 1 n + 1 ) } { 6 }$
E) $\frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 3 }$

Question

Use mathematical induction to solve for all positive integers n.​ $1 + 2 + 3 + 4 + \ldots + n = ?$ ​
A) $\frac { n ( n + 1 ) } { 2 }$
B) $\frac { ( n + 1 ) } { 2 }$
C) $\frac { n } { 2 } ( 3 n + 1 )$
D) $\frac { n ( n + 1 ) ( 1 n + 1 ) } { 6 }$
E) $\frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 3 }$

Quizplus · Accepted Answer

The sum of the first n positive integers is given by the formula $\frac{n(n+1)}{2}$, which can be proven using mathematical induction.

Use Mathematical Induction to Solve for All Positive Integers N 1+2+3+4+…+n=?1 + 2 + 3 + 4 + \ldots + n = ?1+2+3+4+…+n=?

Use Mathematical Induction to Solve for All Positive Integers N $1 + 2 + 3 + 4 + \ldots + n = ?$