Find the probability for the experiment of drawing two marbles (without replacement)from a bag containing 3 green,5 yellow and 4 red marbles such that both marbles are yellow.
A) $$\frac { 2 } { 5 }$$
B) $$\frac { 5 } { 7 }$$
C) $\frac { 25 } { 144 }$
D) $\frac { 25 } { 132 }$
E) $\frac { 5 } { 33 }$

Question

Find the probability for the experiment of drawing two marbles (without replacement)from a bag containing 3 green,5 yellow and 4 red marbles such that both marbles are yellow.
A)​ $$\frac { 2 } { 5 }$$
B)​ $$\frac { 5 } { 7 }$$
C)​ $\frac { 25 } { 144 }$
D)​ $\frac { 25 } { 132 }$
E)​ $\frac { 5 } { 33 }$

Quizplus · Accepted Answer

The probability of drawing the first yellow marble is 5/12. After drawing one yellow marble, there are 4 yellow marbles left out of a total of 11 marbles. So, the probability of drawing a second yellow marble is 4/11. The combined probability is (5/12) * (4/11) = 20/132 = 5/33.

Find the Probability for the Experiment of Drawing Two Marbles 25\frac { 2 } { 5 }52​

Find the Probability for the Experiment of Drawing Two Marbles $\frac { 2 } { 5 }$