A proton moving along the x axis has an initial velocity of 4.0 * 10⁶ m/s and a constant acceleration of 6.0*10¹² m/s².What is the velocity of the proton after it has traveled a distance of 80 cm? A)5.1 * 10⁶ m/s B)6.3 * 10⁶ m/s C)4.8 * 10⁶ m/s D)3.9 * 10⁶ m/s E)2.9 * 10⁶ m/s

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Quizplus · Accepted Answer

Explanation:The velocity of the proton after it has traveled a distance of 80 cm is given by:$$v^2 = u^2 + 2as$$where:* v is the final velocity* u is the initial velocity* a is the acceleration* s is the distance traveledSubstituting the given values into the equation, we get:$$v^2 = (4.0 	imes 10^6 \ m/s)^2 + 2(6.0 	imes 10^{12} \ m/s^2)(0.80 \ m)$$$$v^2 = 1.60 	imes 10^{13} \ m^2/s^2$$$$v = 4.0 	imes 10^6 \ m/s$$Therefore, the velocity of the proton after it has traveled a distance of 80 cm is 4.0 × 10^6 m/s.

A Proton Moving Along the X Axis Has an Initial