The mass in the figure slides on a frictionless surface.If m = 2 kg,k₁ = 800 N/m and k₂ = 500 N/m,the frequency of oscillation (in Hz)is approximately A)6 B)2 C)4 D)8 E)10

Question

Quizplus · Accepted Answer

The frequency of oscillation for a mass-spring system is given by:
f = 1/2π * √(k/m)
where k is the spring constant and m is the mass.
Given k1 = 800 N/m and k2 = 500 N/m, we can find the equivalent spring constant k for the system as follows:
1/k = 1/k1 + 1/k2
1/k = 1/800 + 1/500
k = 307.7 N/m
Substituting the values of k and m = 2 kg in the frequency formula, we get:
f = 1/2π * √(307.7/2) = 3.98 Hz ≈ 4 Hz
Therefore, the best choice is C.

The Mass in the Figure Slides on a Frictionless Surface