Two identical strings have the same length and same mass per unit length.String B is stretched with four times as great a tension as that applied to string A.Which statement is correct for all n harmonics on the two strings,n = 1,2,3...? A) $f _ { \mathrm { nb } } = \frac { 1 } { 4 } f _ { \mathrm { nA } }$ . B) $f _ { \mathrm { nb } } = \frac { 1 } { 2 } f _ { \mathrm { nA } }$ . C) $f _ { n , B } = \sqrt { 2 } f _ { n , A }$ . D)f_n,B = 2f_n,A. E)f_n,B = 4f_n,A.

Question

Quizplus · Accepted Answer

The frequency of a harmonic on a string is proportional to the square root of the tension. Since string B has four times the tension of string A, the frequency of the nth harmonic on string B will be twice that of the nth harmonic on string A.

Two Identical Strings Have the Same Length and Same Mass fnb=14fnAf _ { \mathrm { nb } } = \frac { 1 } { 4 } f _ { \mathrm { nA } }fnb​=41​fnA​

Two Identical Strings Have the Same Length and Same Mass $f _ { \mathrm { nb } } = \frac { 1 } { 4 } f _ { \mathrm { nA } }$