Transverse waves y₁ = A₁ sin(k₁x - $ \omega $₁t)and y₂ = A₂ sin(k₂x - $ \omega $₂t),with A₂ A₁,start at opposite ends of a long rope when t = 0.The magnitude of the maximum displacement,y,of the rope at any point is A)A₁- A₂. B)A₂- A₁. C)A₁ + A₂. D) $\left( A _ { 1 } - A _ { 2 } \right) \frac { k _ { 1 } } { k _ { 2 } }$ . E) $\left( A _ { 2 } - A _ { 1 } \right) \frac { k _ { 2 } } { k _ { 1 } }$ .

Question

Transverse waves y₁ = A₁ sin(k₁x - $ \omega $₁t)and y₂ = A₂ sin(k₂x - $ \omega $₂t),with A₂ > A₁,start at opposite ends of a long rope when t = 0.The magnitude of the maximum displacement,y,of the rope at any point is A)A₁- A₂. B)A₂- A₁. C)A₁ + A₂. D) $\left( A _ { 1 } - A _ { 2 } \right) \frac { k _ { 1 } } { k _ { 2 } }$ . E) $\left( A _ { 2 } - A _ { 1 } \right) \frac { k _ { 2 } } { k _ { 1 } }$ .

Quizplus · Accepted Answer

The maximum displacement occurs when the two waves are in phase, resulting in constructive interference, which is the sum of their amplitudes, A₁ + A₂.

Transverse Waves Y1 = A1 Sin(k1x - ω \omega ω 1t)and Y2 = A2 Sin(k2x -

Transverse Waves Y₁ = A₁ Sin(k₁x - $\omega$ ₁t)and Y₂ = A₂ Sin(k₂x -