Determine the equivalent capacitance of the combination shown when C = 15 mF.
A)20 mF
B)16 mF
C)12 mF
D)24 mF
E)75 mF

Question

Determine the equivalent capacitance of the combination shown when C = 15 mF. 
A)20 mF 
B)16 mF 
C)12 mF 
D)24 mF 
E)75 mF

Quizplus · Accepted Answer

First, we can simplify the parallel combination of 15 mF and 10 mF to get an equivalent capacitance of 6 mF:

C_eq = C_1 + C_2

C_eq = 15 mF + 10 mF

C_eq = 25 mF

C_eq = 1 / (1/C_1 + 1/C_2)

C_eq = 1 / (1/15 mF + 1/10 mF)

C_eq = 6 mF

Then, we can simplify the series combination of 6 mF and 9 mF to get an equivalent capacitance of 3.6 mF:

C_eq = C_1 * C_2 / (C_1 + C_2)

C_eq = 6 mF * 9 mF / (6 mF + 9 mF)

C_eq = 54 mF / 15 mF

C_eq = 3.6 mF

Therefore, the equivalent capacitance of the entire combination is 3.6 mF, which corresponds to choice C.

Determine the Equivalent Capacitance of the Combination Shown When C