Determine the potential difference,V_A - V_B,in the circuit segment shown below when I = 2.0 mA and Q = 50 $\mu$C. A)-40 V B)+40 V C)+20 V D)-20 V E)-10 V

Question

Quizplus · Accepted Answer

The potential difference across the capacitor Q is given by Q/C, where Q is the charge on the capacitor and C is the capacitance. Here, Q = CV, where V is the potential difference across the capacitor plates. We can write V = V_A - V_B. Solving for V, we get V = Q/C = (50 F1F1F1S1F1F1F10C)*(2.0 mA)*(1 F1F1F1s1F1F1F13) = 100 F1F1F1S1F1F1F1020 V. Therefore, the answer is D, F1F1F1S1F1F1F1020 V.

Determine the Potential Difference,VA - VB,in the Circuit Segment Shown μ\muμ

Determine the Potential Difference,V_A - V_B,in the Circuit Segment Shown $\mu$