An electron follows a circular path (radius = 15 cm)in a uniform magnetic field (magnitude = 3.0 G).What is the period of this motion?
A)0.12 $\mu$s
B)1.2 ms
C)0.18 $\mu$s
D)1.8 ms
E)1.8 $\mu$s

Question

Quizplus · Accepted Answer

Explanation:The period of circular motion of an electron in a magnetic field is given by:T = 2πr / vwhere r is the radius of the circular path and v is the speed of the electron.The speed of the electron is given by:v = eB / mwhere e is the charge of the electron, B is the magnitude of the magnetic field, and m is the mass of the electron.Substituting the given values into these equations, we get:T = 2π(0.15 m) / (1.602 × 10^-19 C)(3.0 × 10^-4 T) / (9.109 × 10^-31 kg)T = 0.12 s

An Electron Follows a Circular Path (Radius = 15 Cm)in μ\muμ

An Electron Follows a Circular Path (Radius = 15 Cm)in $\mu$